0=141-16x^2

Solution for 0=141-16x^2 equation:

0=141-16x^2

We move all terms to the left:

0-(141-16x^2)=0

We add all the numbers together, and all the variables

-(141-16x^2)=0

We get rid of parentheses

16x^2-141=0

a = 16; b = 0; c = -141;
Δ = b2-4ac
Δ = 02-4·16·(-141)
Δ = 9024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9024}=\sqrt{64*141}=\sqrt{64}*\sqrt{141}=8\sqrt{141}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{141}}{2*16}=\frac{0-8\sqrt{141}}{32}
=-\frac{8\sqrt{141}}{32}
=-\frac{\sqrt{141}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{141}}{2*16}=\frac{0+8\sqrt{141}}{32}
=\frac{8\sqrt{141}}{32}
=\frac{\sqrt{141}}{4}
$